This can always be done:
Given nontrivial groups Ai for 0leilen, there exists a group G and a subnormal series H=H0<cdots<Hn=G such that Hi/Hi−1congAi for 0lei<n and such that no shorter subnormal series from H to G exists.
Here is my proof:
We can assume n>1, and we induct on n. By the inductive hypothesis, let W be a group with subnormal series V=V1<cdots<Vn, such that Vi/Vi−1congAi for 1lei<n, and such that there exists no shorter subnormal series for V in W. Write A=A0 and let G be the wreath product of A with W corresponding to the action of W on the right cosets in V. In other words, G=BW is a semidirect product, where BtriangleleftG and B is the direct product of |W:V| copies of A. Also, W acts to permute these direct factors of B, and this action is permutation isomorphic to the action of W on the cosets of V in W. (In fact, we assume that we are given a specific bijection from the set of cosets of V onto the set of direct factors of B.)
Now let C be the product of all of the direct factors of B that correspond to nontrivial cosets of V, and note that bfNW(C)=V. Let H=H0 be the group CV, and for i>0, let Hi=BVi. It is easy to see that H0<H1<cdots<Hn=G is a subnormal series with factors Ai as wanted. We must show that no shorter subnormal series for H exists. Note that the subnormal depth of H1 is exactly n−1. (This can be seen by intersecting a subnornal series for H1 in G with W. This yields a subnormal series for V in W.)
Suppose HtriangleleftK. We argue that BK=BV. Otherwise,
BK>BV, so BKcapW>V. But BK normalizes C since C=BcapH, and this contradicts the fact that V is the full normalizer of C in W. Now if H=K0<K1<cdots<Km=G is a subnormal series for H, then H1=BV=BK1subseteqcdotssubseteqBKm=G is a subnormal series for H1 with length at most m−1, and thus mgen, as wanted.
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