Saturday, 31 May 2008

An example of a Z-PBW algebra which is not a PBW algebra?

I have just rechecked the assertion in the Example at the bottom of page 97 and to the best of my understanding it is correct.



I can imagine one cause of a possible confusion, namely, the variables are not listed in the order of their increase in the sense of the ordering that makes them Z-PBW-generators. The order should be xsigma+1,sigma>ysigma+1,sigma>zsigma+1,sigma, the order of monomials being the lexicographical order corresponding to this order of generators. It is presumed that the surviving monomials in the PBW-basis are those that cannot be expressed as linear combinations of any smaller ones (modulo the relations).



Specifically, the quadratic monomials that do not survive (do not belong to the set Ssigma+1,sigma1) are xsigma+1,sigmaysigma,sigma1 and xsigma+1,sigmazsigma,sigma1. Given their form, it is immediately clear that the PBW condition is satisfied.



UPDATE. Well, another source of a possible confusion is a misprint in our formulas. It should be bsigma+1=1/csigma and csigma+1=1/(absigma) and not the other way around. To put it simply, the constants bsigma and csigma are chosen in such a way that the terms xsigma+1,sigmaxsigma,sigma1 cancel out in each relation.

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