This is a property of mu, not that of mathcalA, and it is called being atomless. It is equivalent to not having sets AinmathcalA of positive measure such that for all BinmathcalA, BsubseteqA the measure mu(B) is either 0 or mu(A).
edit: Wikipedia article, complete with the proof of the property you describe from atomlessness.
edit: yup, the comments are right and I'm wrong. The precise condition for finite measures composed entirely of atoms to have full range is anleqsumj>naj - it is clearly necessary as an−varepsilon has to be produced somehow, and the greedy algorithm shows sufficiency.
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