"Smaller" in the sense of le ... If S is closed and has Hausdorff dimension <n, then S has empty interior, so (as noted by Joel) S is its own boundary, and thus we have equality for the two dimensions. And of course if (perhaps not closed) set S has dimension n, then the boundary could have any dimension from 0 to n, inclusive. If S is closed and has dimension n, then the boundary is either empty or has dimension gen−1.
No comments:
Post a Comment