I don't know a name, but I'll give you a different characterization. Biconnectivity is sufficient but too strong, while "having minimum degree at least 2" is necessary but too weak. I'm almost certain this is a necessary and sufficient condition:
G has minimum degree at least 2, and if v is a cutvertex of G, then there is some new connected component of G−v with at least two vertices adjacent to v.
Here's a proof of sufficiency: If v is not a cutvertex of G, then pick any two vertices adjacent to v. There's a path between them not going through v (since G−v is connected), so v is contained in a cycle.
If v is a cutvertex of G, then pick the two vertices adjacent to v that are in the same connected component of G−v. There's a path between them that extends to a cycle containing v.
Now, a proof of necessity. Suppose that G has a cutvertex v whose removal does create deg(v)-1 new connected components. Then v can't lie in a cycle. (This is easy to check.)
This characterization is equivalent to: Removing any vertex of degree d increases the total number of connected components by at most d−2. Some generalization of this property may have a name.
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