This is a sideways answer.
Let Eij(a)=I+aEij, for ineqj and ainA.These matrices generate the conmutator subgroup E(n,A)=[mathrmGL(n,A),mathrmGL(n,A)]subseteqmathrmGL(n,A).
One can easily check that the obvious relations satisfied by these elements are Eij(a)Eij(b)=Eij(a+b),
Yet the group presented by generators and this relations is not E(n,A), but what we call the ∗n-th unstable Steinberg group* mathrmSt(n,A) of A. In general, this is larger than (precisely, an extension of) E(n,A).
(NB: The following paragraph has been edited to make it match reality. Thanks to Allen for pointing the mistake in the comment bellow)
This is seen, for example, because the map mathrmSt(n,A)toE(n,A) has a non-trivial kernel. Indeed, after passing to the direct limit as n goes to infinity, the kernel of that map is precisely the second algebraic K-theory group of A, K2(A). Milnor shows in his book that K2(mathbbR) is uncountable, and describes K2(mathbbQ) (he also shows that K2(mathbbZ) is cyclic of order two, so this can be done for rings that are not fields too...)
A nice reference for all this is Jonathan Rosenberger's Algebraic K-theory and its applications, and there is John Milnor's Introduction to algebraic K-theory, which is also extremely nice.
A short intuitive description for K2(A) is: it measures how much more information is there in the elementary matrices of a ring which does not follow formally from the Steinberg relations.
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