This is hardly an astronomy question, but I like drawing, so here you are:
Longitudes are measured from the Greenwich meridian, so the angle between Kampala and Quito is
thetamathrmQ+thetamathrmK=82.5circ+37.5circ=110circ.
(remember that 0circ30′=0.5circ).
The shortest surface path is along Equator. Since 110circ is frac110circ360circsimeq0.3 times the circumference of Earth at Equator, the length of path A (the dashed line) is
mathrmA:,,d=0.3times40,075,mathrmkm=12,245,mathrmkm
For path B (the solid line), you need a bit more trigonometry. The radius of Earth is R=40,075,mathrmkm,/,2pi=6,378,mathrmkm. The rest will be left as an exercise.
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