Here's a case where G and H can be conjugate. First some notation: given a sequence kn of positive integers, let [k1,k2,ldots] denote the permutation
(1,ldots,k1)(k1+1,ldots,k1+k2)(k1+k2+1,ldots,k1+k2+k3)cdots
with cycles of size k1,k2,k3ldots. For example, [1,1,1,1,ldots] denotes the identity, [2,2,2,2,ldots] denotes (1,2)(3,4)(5,6)(7,8)cdots, and [2,3,2,3ldots] denotes (1,2)(3,4,5)(6,7)(8,9,10)cdots.
Let
g=[1,2,;;1,2,4,;;1,2,4,8,;;ldots],
let
h=[1,1,1,;;1,1,1,2,2,;;1,1,1,2,2,4,4,;;ldots],
and let G and H be the cyclic subgroups generated by these elements. Since g and h have the same cycle structure, they are conjuagte in Sym(mathbbN), so G and H are conjugate subgroups.
However, for sufficiently large n, the orbit of (pi(1),pi(2),ldots,pi(n)) under G will be precisely twice the size of the orbit under H.
Of course, in this example G and H both have infinitely many orbits of size 2k for every k, so this does not answer the more restrictive version of the question.
No comments:
Post a Comment