The strong magnetic fields in neutron stars are supposed to come from magnetic flux conservation. If we have:
$Phi_B = int B dS = const$
where $Phi_B$ is the magnetic field flux, $B$ is the magnetic field strength, and $dS$ is the elemental closed surface; then, this integral is constant through the surface.
If we consider the star surface over which take the integral, than
$S = 4pi R^2$
where $R$ is the star radius. This can be translated, altogether with the magnetic flux conservation law, as:
$B_f = B_i (frac{R_i}{R_f})^2$
where $i$ and $f$ are the indices for initial and final stages.
We know that the star implodes from a whatever star size to $sim10$ km. So the radii ratio is huge. You just need a starting magnetic field of $10-100$ G, to get a final magnetic field of the order of $10^{12}$ G, that is typical in neutron stars.
No comments:
Post a Comment