We can assume that the stars are equal in mass, and their orbits are circular
The orbital speed is 80000 m/s and at an orbital period of 10 months (or 2.628times107s) the length of the orbit is 2.1024times1012 m or 14.05 AU The radius of the orbit therefore is 14.05/tau = 2.237AU.
The version of Keplers law given is T2=fraca3m1+m2
substituting T2=(10/12)2=0.6944 (divide by 12 to convert to years) and a3=11.19 gives m1+m2=frac11.190.6944=16.12mathrmsolarmass.
Since m1=m2, the mass of each star is 8.06 solar masses, or 1.6times1031kg
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