You're correct that "$p$-wave" in this context means that the charmonium has orbital angular momentum $L=1$. The principal observable effect is that two-particle states with even $L$ have even parity, while those with odd $L$ change sign under parity.
If you were to skim the Particle Data Group's list of charmonia (or the $cbar c$ section of the short list) you would find that each particle has a value listed for spin, $J$, and parity, $P$. The lightest few states are
$eta_c(1S)$, with $J^P = 0^-$. This is a charm-anticharm bound state where the two quarks have opposite spins and the angular momentum $L=0$. (The total parity is negative because the intrinsic parities of the $c$ and $bar c$ have opposite sign.)
$J/psi(1S)$, with $J^P=1^-$. This has the same parity as the spinless $eta_c$, but a unit of spin. So it must be that here the two quarks have the same spin and $L=0$.
$chi_{c0}(1P)$, with $J^P=0^+$. The change in parity suggests that this state must have a different $L$ than the $eta_c$ and $J/psi$, and it's the first with a $P$ in its name. There's also a $chi_{c1}$ and $chi_{c2}$ with $J^P=1^+, 2^+$, respectively. That suggests these are the three spin combinations of a charm-anticharm pair with spin $S=1$ and orbital angular momentum $L=1$.
There are also some charmonia with $(2S)$ and $(2P)$ in their names. There don't appear to be any definitively labeled $d$-wave charmonia.
No comments:
Post a Comment