Suppose you have a curve $C$ such that deg$K_C =0$ and $Gamma(C,Omega_C^1) neq 0$. Does this automatically imply that $vartheta_C equiv Omega_C^1$? My thought is yes, I've seen a proposition (Stanford AG course notes) that $vartheta_C equiv Omega_C^1$ for a nonsingular plane cubic, but the proof is done in a particular case, and I must think there is easier way to show this. In particular, what is the morphism?
Thank you, just trying to make sense of this concept.
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