I believe your example is correct. As you are allowing A closed the following is pretty similar. Choose a real number N>1. Take the smooth and analytic curve (write it as a level curve and check the gradient) y2=x3−3N2x2+3N4x=left(fracx4right)left((2x−3N2)2+3N4right)
Note that 2yy′=3x2−6N2x+3N4=3(x−N2)2.
Also 4y3y″=3(x4−4N2x3+6N4x2−3N8)=3left((x−N2)4+4N6(x−N2)right).
Furthermore, when x=N2,y=pmN3.
Revolve this around the x-axis, making a simply connected surface. There is now a closed geodesic along x=N2, of circumference 2piN3. The minimizing geodesic between
(N2,N3,0) and (N2,−N3,0) is the original curve in the plane z=0, of length no larger than 2N2+2N3. The length of half the closed geodesic is piN3, which is larger for large enough N. So, as I did not say, we are taking N>2 and
A=left(x,y,z)inmathbbR3:y2+z2=x3−3N2x2+3N4x;mboxand;xleqN2.right
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