riemann surfaces - Weil's theorem about maps from a discrete group to a Lie group.

Let K be a group (with discrete topology), G be a Lie group. Let $operatorname{Hom}(K,G)$ be the space of all group homomorphisms from K to G. This is a closed subvariety of the space of all the maps from the generators of K to G, and as such has a topology.

Andre Weil's paper "On Discrete Subgroups of Lie Groups" proves that an important subset $U subset operatorname{Hom}(K,G)$ is open. U is defined as the set of all homomorphism $Kto G$ such that the homomorphism is injective, the image is discrete, and the quotient $G/image(K)$ is compact.

Questions:

1. What happens if you remove the condition that the quotient is compact?




2. How often/where is this taught? What kinds of books would it be in, what kind of courses would have it? This looks like a basic result that could be taught anywhere,
   but it's completely new to me (not that I know much about representation theory).
   while Weil's paper fortunately seems very readable, I couldn't easily find any other
   source that would such questions.

Motivation:

In the case where $K=pi_1 (S)$ is the fundamental group of a surface and $G=PSL_2(mathbb R)$, the space $operatorname{Hom}(K,G)$ is very closely related to the Teichmuller space of S. Every Riemann surface is a quotient of $PSL_2(mathbb R)$ by a discrete subgroup. So, for an element of $operatorname{Hom}(K,G)$, the quotient $G/image(K)$ corresponds to a Riemann surface and the data of the actual map $Kto G$ gives a marking on it.

Not every homomorphism $Kto G$ corresponds to a point of Teichmuller space. For example, the map that sends all of K to the identity is clearly no good, as the quotient $K/G$ is not topologically the same as the surface S. However, if the map is injective and the image of K in G is discrete, all will be well. So, Weil's theorem basically says that the Teichmuller space of S is an open subset of $operatorname{Hom}(pi_1(S),PSL_2(mathbb R))$.

However, since Weil's theorem requires the quotient to be compact, this won't work if S is a non-compact Riemann surface. I wonder how much more difficult life becomes in this case.

Disclaimer/Another question:

The above has a small lie in it. To get the Teichmuller space, you actually need to look at the quotient $operatorname{Hom}(K,G)/G$ where G acts on $operatorname{Hom}(K,G)$ by conjugation of the target. In the case of compact surfaces, this is not supposed to mess up the fact that the subset is open; this seems to be a result of William Goldman but I don't have the exact reference. If you can say anything about this, I'd appreciate it too.

Thank you very much!

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