Thursday, 9 April 2009

measure theory - A question about sigma-ring

How about choosing B=B1B2 and C=C1C2, we have BinS(EcapA) by property of S(EcapA), and CinS(E), by property of S(E).



The fact that this works can be seen by observing that both B1cup(C1A), and B2cup(C2A) are in fact both disjoint unions. B1,B2 has everything to do with A and C1A,C2A has nothing to do with A at all.



ps: I don't know why you use the and and or symbol here instead of intersection and union symbol.

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