I'm happy to present my example of a smooth projective surface X over
K=mathbbQp (p prime) such that X(K)neqemptyset, whose
l-adic cohomology groups are unramified (for all primes l) and which still
has bad reduction : there is no smooth mathbbZp-scheme whose generic
fibre is X. (The method works for any finite extension of mathbbQp and was worked out a few years ago.)
The surface X is going to be a conic bundle over mathbbP1 with four
degenerate fibres, so it is a rational surface in the sense of being barK-birational to mathbbP2. It will be clear that the example is not
isolated.
If p is odd, let dinmathbbZtpimes be a unit which is
not a square, and take d=5 if p=2, so that K(sqrtd)|K is the unramified quadratic extension.
Let e1,e2 be two distinct units of K. We take X to be the surface in
mathbbP(calO(2)opluscalO(2)opluscalO) (coordinates y:z:t)
over mathbbP1 (coordinates x:x′) defined by the equation
y2−dz2=xx′(x−e1x′)(x−e2x′)t2.
I claim that this X has all the properties stated above, if vp(e1−e2)>0.
First, X(K)neqemptyset because each degenerare fibre is a pair of
intersecting lines conjugated by mathrmGal(barK|K).
Secondly, the l-adic cohomology is unramified because the action of
mathrmGal(barK|K) on the Picard group mathrmPic(barX) of barX=XtimesKbarK factors via the quotient mathrmGal(K(sqrtd)|K).
Finally, X has bad reduction because its Chow group A0(X)0 of 0-cycles of degree
0 is mathbbZ/2mathbbZ (cf. prop. 1 of arXiv:math/0302156), and a theorem of Bloch (th. 0.4, On the Chow groups of certain
rational surfaces, Annales scientifiques de l'École Normale Supérieure, Sér.
4, 14 no. 1 (1981), p. 41-59, available at Numdam) asserts that if a conic bundle has good
reduction, then its Chow group of 0-cycles of degree 0 is 0.
Addendum (in response to a question in an email I received). One can show moreover that no smooth projective surface Y over mathbfQp which is mathbfQp-birational to X can have good reduction. This follows from the facts recalled above and the theorem of Colliot-Thélène and Coray (which can be found in Fulton's Intersection theory) : A0(Y)0 is isomorphic to A0(X)0.
No comments:
Post a Comment