We know that limprightarrowinftyleftVertleft(x1,cdots,xnright)rightVertp=maxleftleft|x1right|,cdots,left|xnright|right=:leftVertxrightVertinfty
for any left(x1,cdots,xnright)inRn. Now
do we have limprightarrow0leftVertleft(x1,cdots,xnright)rightVertp=leftVertleft(x1,cdots,xnright)rightVert0:=mboxcardinalityleftxi:xineq0right?
Tuesday, 22 June 2010
ca.analysis and odes - On the extension of a limit
at
20:23
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Mathematics

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