Now, since you call erfc(1) "a closed form expression", I should confess I do not understand the rules of this game. What's the big difference between inti1nftye−x2/2dx and the original integral? Or, do you ask if it is an elementary function of the parameter c?
If the latter, note that the function J(c)=ec2inti−inftynftyfrace−(x−c)21+x2dx satisfies the equation J″+4J=4sqrtpiec2, which, if you try to solve it by the method of variation of parameters, leads to the indefinite integrals like intec2cos2cdc. Those are not elementary, but not much worse than your erfc.
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