At least if you're talking about finite coproducts, then the answer is yes. If nlem, then we have a canonical inclusion sumni=11hookrightarrowsummj=11, which is in fact a complemented subobject with complement summ−nk=11. If this inclusion is an isomorphism, then its complement is initial, and hence (assuming the topos is nontrivial) n=m. Now if we have an arbitrary isomorphism sumni=11congsummj=11, then composing with the above inclusion we get a monic summi=11hookrightarrowsummj=11. However, one can show by induction that any finite coproduct of copies of 1 in a topos is Dedekind-finite, i.e. any monic from it to itself is an isomorphism. (See D5.2.9 in "Sketches of an Elephant" vol 2.) Thus, the standard inclusion is also an isomorphism, so again n=m.
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