First of all, your first question.
This source clearly state that Values are given in the usual logarithmic (dex) scale
, for the same formula that you quoted (similar job).
It is a bit tricky as the article "explains" the values, but you have to pay attention to the exact definition.
I think it is better to work out with an example. Let's take the He
.
Good enough, you can better read the paper from here.
From the table, we have $A_{el}=10.93$. This is the abundance of He relative to H (in logarithmic scale).
From this you find out that $frac{N_{el}}{N_H}=0.08 = 8%$.
Indeed the work confirms this value (see the last page).
What you quote as about 25% He
, is what they call abundances by mass of [...] Helium (Y)
, which means $Y = mass of Helium / mass of Hydrogen$, and this is indeed about $25%$.
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