Chapter 5.5 of Concrete Mathematics discusses generalizing binomial coefficient identities to the Gamma function. It doesn't discuss the two integrals you mention, though.
Doing a bit of thinking on my own, if n is a positive integer then
intnz=0binomnzdz=intnz=0fracn!dzGamma(1+z)Gamma(n+1−z)
intnz=0fracn!dz(n−z)(n−1−z)cdots(1−z)Gamma(1−z)Gamma(1+z).
We have Gamma(1+z)Gamma(1−z)=piz/sin(piz), if I haven't made any dumb errors, so this is
intn0fracn!sin(piz)dzpiz(n−z)(n−1−z)cdots(1−z).
I suspect this integrand does not have an elementary anti-derivative, because it reminds me of intsintdt/t. But there might be some special trick which would let you compute the integral between these specific bounds.
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