This might help.
Lemma If A does not split freely and C is a non-trivial subgroup of A then the HNN extension G=A∗C does not split freely.
The proof uses Bass--Serre theory---see Serre's book Trees from 1980.
Proof. Let T be the Bass--Serre tree of a free splitting of G. Because A does not split freely, A stabilizes some unique vertex v. But C is non-trivial, so C also stabilizes a unique vertex, which must be v. Therefore, G stabilizes v, which means the free splitting was trivial. QED
A similar argument shows the following.
Lemma If A∗C splits non-trivially as an amalgamated free product A′∗C′B′ then either A splits over C′ or C is conjugate into C′.
No comments:
Post a Comment