Ok Ady, since you like CH I will work with CH, and to make your life
easier, I will work with GCH.
Since I do not expect that everybody in MO is aware of various
Banach space constructions, let me give some information on James
tree spaces which are relevant to the question.
A tree is a partially order set (T,<) such that for every t in T the
initial segment sinT:s<t is well-ordered under <.
A segment of T is a subset S of T which is:
- linearly ordered under < and
- for all s,t,winT if s<t<w and s,winS then tinS.
The completion of T, usually denoted by c(T), is the collection of all initial
segments of T ordered by inclusion. Notice that c(T) contains T and
is much larger than T. For instance, if T is the tree of all finite sequences
of natural numbers (usually called the Baire tree, which is clearly countable),
then its completion is the Baire-tree together with its branches (i.e. the
Baire space) and so it has the cardinality of the continuum.
For every tree T the corresponding James tree space JT is defined to
be the completion of c00(T) with the norm:
|v|=sup(sumdi=1(sumtinSiv(t))2)1/2
where the above supremum is taken over all finite families (Si)di=1 of
pairwise disjoint segments of T. Basic facts (I can provide appropriate
references to anyone who is interested):
- For every tree T the space JT is hereditarily ell2; that is,
every infinite-dimensional subspace of JT contains a copy of ell2. - For every tree T the second dual of JT is linearly isometric to
the James tree space of the completion c(T) of T. In particular,
neither JT∗ nor JT∗∗ contain a copy of ell1.
Now we come to the specifics of the construction. Remember that we work
with GCH. This implies, in particular, the following: if X is a Banach
space of cardinality kappa, then the algebraic dual of X has cardinality
kappa+.
Let T be the tree of all countable subsets of omega1 equipped
with the partial order of end-extension. We have GCH, hence, the tree
is just all sequences of real numbers, and so, it has cardinality
aleph1. The cardinality of the corresponding James tree space is
also aleph1.
The completion c(T) of our tree T is the set of all subsets of
omega1. Hence it has cardinality 2aleph1 which is,
under GCH, aleph2. It follows that the cardinality of JT∗∗
is aleph2.
Now consider cases.
Case 1: the topological dual JT∗ of JT has cardinality strictly
bigger than aleph1. Then we are done: our counterexample is JT.
Case 2: the topological dual JT∗ of JT has cardinality aleph1.
We are also done: our counterexample is JT∗.
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