Monday, 5 October 2009

nt.number theory - Are the field norm and trace the unique "nice" maps between fields?

Here is a nice characterization of the norm mapping on a finite extension of fields $K/k$.



If $K/k$ is any finite extension of fields with degree $n$, then the norm mapping from $K$ to $k$ is the unique function $f colon K rightarrow k$ satisfying the following three conditions:



1) $f(xy) = f(x)f(y)$ for all $x$ and $y$ in $K$.



2) $f(c) = c^n$ for all $c$ in $k$.



3) $f$ is a polynomial function over $k$ of degree at most $n$, by which I mean there is a basis ${e_1,dots,e_n}$ of $K/k$ relative to which $f$ can be described by a polynomial: there's a polynomial $P(x_1,dots,x_n)$ in $k[x_1,dots,x_n]$ such that $f(sum_{i=1}^n c_ie_i) = P(c_1,dots,c_n)$ for all $c_1,dots,c_n$ in $k$. (Being a polynomial function is independent of the choice of basis.)



This is due to Harley Flanders. See the following two articles of his:



The Norm Function of an Algebraic Field Extension, Pacific J. Math 3 (1953), 103--113.



The Norm Function of an Algebraic Field Extension, II, Pacific J. Math 5 (1955), 519--528.



One nice consequence of this characterization of the norm, which Flanders points out, is that it gives a slick proof of the transitivity of the norm: if $K supset F supset k$ then the function
${rm N}_{F/k} circ {rm N}_{K/F}$ satisfies the three conditions that characterize ${rm N}_{K/k}$.

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