Let H and K be Hilbert spaces, and let u be a partial isometry in mathcalB(HotimesK) between projections p0=uastu and p1=uuast such that p0,p1leq1otimes(1−q) for some projection qinmathcalB(K) equivalent to 1inmathcalB(K). Does p1u(aotimes1)p0=p1(aotimes1)up0 for all aotimes1inmathcalB(H)otimes1 imply that u can be extended to a unitary operator in the commutant (mathcalB(H)otimes1)′=1otimesmathcalB(K)?
I've verified the implication for several simple examples, but I'm having trouble proving it in full generality.
Update: I've reworded the question for clarity thanks to Yemon's comments. By a unitary operator extending u, I mean a unitary operator that agrees with u on p0(mathcalHotimesmathcalK).
Update: Here's one example.
Let K be infinite dimensional with basis e1,e2,ldots, and H be n-dimensional with bases xi1,ldots,xin and zeta1,ldots,zetan. Let xi=frac1sqrtnsumixiiotimesei and zeta=frac1sqrtnsumIzetaiotimesei. Define ucolonetamapstolangleeta,xiranglezeta. Note that the assumptions in the first sentence are satisfied with q the projection on the span of en+1,en+2,ldots. The condition that p1u(aotimes1)p0=p1(aotimes1)up0 for all aotimes1inmathcalB(H)otimes1 is here equivalent to langleu(aotimes1)xi,zetarangle=langle(aotimes1)uxi,zetarangle for all ainmathcalB(H), which is in turn equivalent to langle(aotimes1)xi,xirangle=langle(aotimes1)zeta,zetarangle for all ainmathcalB(H). The latter equation holds because both sides are equal to the trace of a. Thus, all conditions are satisfied.
To see that the conclusion holds, let Kn be the span of e1,ldots,en, and let cij be the unitary ntimesn matrix such that zetai=sumjcijxij. Then uxi=zeta=frac1sqrtnsumizetaiotimesei=frac1sqrtnsumijcijxijotimesei=frac1sqrtnsumjxijotimeswej=(1otimesw)xi,
I realized that the other examples I was thinking about are trivial.
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