I agree with Joel Hamkins's answer, but I don't entirely agree with his comment on that answer. I generally use asterisks to mean "with finitely many exceptions" or "modulo finite sets", so I'd use fleq∗g and Asubseteq∗B as Joel says. But when working modulo some ideal I other than the ideal of finite sets, I'd ordinarily avoid asterisks and instead write fleqIg and AsubseteqIB.
I'd like to protest vigorously against the use of ll in this situation. To me, fllg means that f is a lot smaller than g (at least eventually), whereas here you might have f(n)=g(n)−1 for all n.
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