Here is a useful example of counter-examples in commutative ring theory;
Let R=P(mathbbN) be the power set of mathbbN. It has a ring structure (R,+,times) where + is the symmetric difference of sets and times is the intersection of sets.
Applications:
Obviously, R is a commutative ring with 1, (mathbbN is the 1).
1) Let R be a commutative ring with 1 and a multiplicative closed set of R. If R is Noetherian (Artinian) ring then S−1R is Noetherian (Artinian). Does the converse hold?
No, it doesn't.
Using the above example, for any prime ideal p of R, Rp (the localization at p) is Noetherian (Artinian) while, R is not Noetherian (Artinian).
Outline:
Consider P({1}) subset P({1,2}) subset... and P(mathbbN)supset P(mathbbNsetminus{1}) supset P(mathbbNsetminus{1,2}) supset... showing that R is neither Noetherian nor Artinian ring.
It is easy to verify that Rp is isomorphic to mathbbZ/2, hence it is both Noetherian & Artinian. (Every element of Rp is either 0/1 or a invertible.)
2) Let R be an integral domain (also commutative with 1), then for every multiplicative closed set of R, S−1R is an integral domain, hence for every Rp. Does the converse hold?
By the above example, it doesn't, since (P(mathbbN),+,times) is not an integral domain.
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